Mathematics, 05.05.2020 02:53 lorreee

Arrange the functions in decreasing order of their periods,
y=-3cos(x+2pi)
y=2/3cot(x/4) +6
y=-1/2tan(5x/6+pi
y=5csc(3x)+6
y=-10sin(x/5 - 2pi)

Answers: 1

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Arrange the functions in decreasing order of their periods,
y=-3cos(x+2pi)
y=2/3cot(x/4)...

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More questions: Mathematics Another questions

Arrange the functions in decreasing order of their periods, y=-3cos(x+2pi) y=2/3cot(x/4) +6 y=-1/2tan(5x/6+pi y=5csc(3x)+6 y=-10sin(x/5 - 2pi)

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Another question on Mathematics

Arrange the functions in decreasing order of their periods,
y=-3cos(x+2pi)
y=2/3cot(x/4) +6
y=-1/2tan(5x/6+pi
y=5csc(3x)+6
y=-10sin(x/5 - 2pi)