What are the new vertices of quadrilateral DEFG, if the quadrilateral is translated downward one unit?

A. D’ = (-5,2), E’ = (-3,6), F’ = (5,2), G’ = (3,-2)
B. D’ = (-5,0), E’ = (-3,4), F’ = (5,0), G’ = (3,-4)
C. D’ = (-6,0), E’ = (-4,4), F’ = (4,0), G’ = (2,-4)
D. D’ = (-5,-1), E’ = (-3,3), F’ = (5,-1), G’ = (3,-5)

452,489 to the nearest thousand is 452,000

sine

step-by-step explanation:

86

step-by-step explanation:

find the area of the triangle then multiply by 2 then add the area of the parollelegram multiplied by 2

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

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