For a moving object the force acting on the object varies directly from the objects acceleration when a force of 25 N acts on a certain object the acceleration of the object is 5 m/s2 top of two if the force exchange to 10 N what will be the acceleration of the object

2m/s²

Step-by-step explanation:

If for a moving object the force acting on the object varies directly from the objects acceleration, then it can be expressed as:

F∝a

F = ka.

F is the force

a is the object's acceleration

From the expression;

k is the constant of proportionality

When an initial force of 25 N acts on the object and the acceleration of the object is 5 m/s², then

k = 25/5

k = 5Ns²/m

If the force exchange to 10 N, the acceleration of the object will be gotten using the relationship above

F = ka

Given F = 10N and k = 5Ns²/m

a = F/k = 10/5

a = 2m/s²

The acceleration of the object will be 2m/s²

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!