I NEED HELP FAST WILL GIVE BRAINLIEST A quiz has 3 multiple-choice questions with 4 possible answer choices each. For each question, there is only 1 correct answer. A student chooses each answer at random. What is the probability that the student will answer all three questions correctly? 6.25%

0.01562%

1.5625%

15.625%

1.5625%

Step-by-step explanation:

P(correct) = 1/4

Since all the attempts are independent, probability of all three correct is:

¼ × ¼ × ¼

1/64

1/64 × 100

1.5625%

0.01562%

Step-by-step explanation:

Since there are 3 questions with 4 answer choices, and only one is correct. You will need to multiply 1/4 three times to give you the answer if he got them all right.

××=

Divide this to find the percent, which is 0.01562%

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

i would need to see the dot plot : )