Explain how you could use 25% of a number to find a number.

Multiplying any number by .25

Step-by-step explanation:

This is dependent on what number you are trying to find.

To find 25% of a number; multiply the number by .25 (This is most common)

To find a 25% discount; multiply by .25 then subtract that number from the original number (e.x. 100 x .25 = 25 then 100 - 25 = 75)

These are the two most common, if there is another way you are trying to find feel free to comment, or shoot me a message. I am happy to help!

it would be:

c.parallelogram.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)