If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t circle s) (x)?
4(x – 7)2 – x – 7 + 3
4(x – 7)2 – (x – 7) + 3
(4x2 – x + 3) – 7
(4x2 – x + 3)(x – 7)

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step-by-step explanation:

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)