SOLVE IT! IT MUST BE EGAL WITH ,,1".
I need step by step explain

x = 0

Step-by-step explanation:

-[(3^x - 1)(5^x - 1)] + 1 = 1

Subtract 1 form both sides

-[(3^x - 1)(5^x - 1)] = 0

Divide both sides by -1

(3^x - 1)(5^x - 1) = 0

Equate the factors to 0

3^x - 1 = 0

3^x = 1

Use ln both sides

ln(3^x) = ln(1)

xln(3) = 0

x = 0

5^x - 1 = 0

5^x = 1

Use ln both sides

ln(5^x) = ln(1)

xln(5) = 0

x = 0

The only solution is x = 0

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.