Which of the following options correctly represents the complete factored form of the polynomial F(x)=x^4-3x^2-4?

A. F(x)=(x+1)(x-1)(x+2)(x-2)

B. F(x)=(x+i)(x-i)(x+2i)(x-2i)

C. F(x)=(x+1)(x-1)(x+2i)(x-2i)

D. F(x)=(x+i)(x-i)(x+2)(x-2)

D

Step-by-step explanation:

Let's substitute a for x²:

x^4 - 3x² - 4

a² - 3a - 4

Now, this looks like something that is much more factorisable:

a² - 3a - 4 = (a - 4)(a + 1)

Plug x² back in for a:

(a - 4)(a + 1)

(x² - 4)(x² + 1)

The first one is a difference of squares, which can be factored into:

x² - 4 = (x + 2)(x - 2)

The second one can also be treated as a difference of squares:

x² + 1 = x² - (-1) = (x + √-1)(x - √-1) = (x + i)(x - i)

The answer is (x + 2)(x - 2)(x + i)(x - i), or D.

F(x)=x⁴-3x²-4

x⁴-3x²-4=

=x⁴-4x²+ x²-4

=x²(x²-4)+(x²-4)

=(x²+1)(x²-4)

=(x+i)(x-i)(x+2)(x-2)

F(x)= (x+i)(x-i)(x+2)(x-2)   D.

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation:

i think the answer is a.( -3, -1 )