Finding Coordinates



Use the graph to find the coordinates of each vertex in triangle ABC.

X (–2, –3)(–2, 3)(3, –2) is the coordinate of Point A.

(2, 4)X (4, 2)(–2, 3) is the coordinate of Point B.

(0, –1)(1, 0)X (–1, 0) is the coordinate of Point C.

On a coordinate plane, point A is (negative 2, 3), point B is (2, 4), and point C is (0, negative 1). The points are connected with lines.

Use the graph to find the coordinates of each vertex in triangle ABC.

✔ (–2, 3)

is the coordinate of Point A.

✔ (2, 4)

is the coordinate of Point B.

✔ (0, –1)

is the coordinate of Point C.

I just did the quiz sorry that this is late

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

f(x) = y

f(-3) = -5

step-by-step explanation: