Mr. Prescott asks all the students in his class whether they play sports. A randomly selected student in his class is more likely to play sports than not to play sports. A. What is a possible probability that a randomly selected student from Mr. Prescott's class plays sports? B. Based on your probability in part A, what is a possible probability that a randomly selected student from Mr. Prescott's class does not play sports?

A. .6

B. .4

Step-by-step explanation:

Based on the information given, we know that the students are more likely to play sports than not. This means that the probability they play sports must be greater than half or greater than .5.

P(play sports) > .5

P(not play sports) < .5

They can't be equal to .5, because then there would be an equal chance of playing sports and not playing sports!

A. A possible probability is .6 for playing sports. Anything over .5 will work.

B. A possible probability is .4 for not playing sports. Anything under .5 will work.

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560