How do you express one half of the difference of a number cubed and one?

(1/2)(n^3 - 1)

Step-by-step explanation:

Let the number be n.  Then "a number cubed" less 1 is n^3 - 1 (same as "difference of a number cubed and one).

Half of this result is (1/2)(n^3 - 1)

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer