Omposite figure is divided into two congruent trapezoids, each with a height of 4 cm. 2 trapezoids. Both trapezoids have base lengths of 10 centimeters and 6 centimeters, and a height of 4 centimeters. Trapezoid area: A = one-half (b 1 + b 2) h What is the area of this composite figure? 32 centimeters squared 40 centimeters squared 64 centimeters squared 80 centimeters squared

Option C:

64 \ cm^2 is the area of the composite figure

It is given that the composite figure is divided into two congruent trapezoids.

The measurements of both the trapezoids are

b_1=10 \ cm

b_2=6 \ cm and

h=4 \ cm

Area of the trapezoid = \frac{1}{2} (b_1+b_2)h

Substituting the values, we get,

A=\frac{1}{2} (10+6)4

A=\frac{1}{2} (16)4

A=32 \ cm^2

Thus, the area of one trapezoid is $32 \ {cm}^{2}$

The area of the composite figure can be determined by adding the area of the two trapezoids.

Thus, we have,

Area of the composite figure = Area of the trapezoid + Area of the trapezoid.

Area of the composite figure = $32 \ {cm}^{2}+32 \ {cm}^{2}$ = 64 \ cm^2

Thus, the area of the composite figure is 64 \ cm^2

Step-by-step explanation:

q: 92 degrees

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can you rephrase the question ? it is unclear : -)

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