The figures are similar. Give the ratio of the perimeters and the ratio of the areas of the first figure to the second. 8 and 18

A. 4:9 and 16: 81
B. 4:9 and 25: 100
C. 5:10 and 25: 100
D. 5:10 and 16: 81

A

Step-by-step explanation:

The ratio of the perimeters is equal to the ratio of the sides.

Given ratio of sides = a : b, then

ratio of areas = a² : b²

Here ratio of sides = 8 : 18 = 4 : 9, thus

ratio of perimeters = 4 : 9 and

ratio of areas = 4² : 9² = 16 : 81

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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