![\frac{[2(x+3)(x+2)]-[2(2x+6)]}{(2x+6)(x+3)(x+2)} = \frac{3}{(x+3)}](/tpl/images/0632/1969/1b7af.png)
![\frac{[(2x+6)(x+2)]-(4x-12)}{(2x+6)(x+3)(x+2)} = \frac{3}{(x+3)}](/tpl/images/0632/1969/9e0cc.png)
and obtain real values of x. Therefore, there are no real solutions.Solve the equation, using any method. Be sure to check for extraneous solutions.
2/(2x+6) - 2...
Mathematics, 05.05.2020 03:07 natalie2sheffield
Solve the equation, using any method. Be sure to check for extraneous solutions.
2/(2x+6) - 2/x^2+5x+6= 3/(x+3)
Answers: 1
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