Write a polynomial expression for the perimeter of a triangle whose sides have the following lengths.
X + 8, 3x^2 +4x X^2 - 3x + 6
A. 4x^2 + 5x + 6
B. 3x^2 + 2x + 2
C. 4x^2+2x+14
D. 3x^2 + 8x + 8

only 10/60 isn't equivalent

hope this : )

sadsdda

step-by-step explanation:

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)