Consider the following series. [infinity] n = 1 3n + 14−n Determine whether the geometric series is convergent or divergent. Justify your answer. Converges; the series is a constant multiple of a geometric series. Converges; the limit of the terms, an, is 0 as n goes to infinity. Diverges; the limit of the terms, an, is not 0 as n goes to infinity. Diverges; the series is a constant multiple of the harmonic series.