∆XYZ has vertices X(0, 3), Y(2, 0), and Z(4, 2). If you reflect ∆XYZ across the line x = 4, what will be the coordinates of the vertices of the image ∆X′Y′Z′?

A.) X′(4, 3), Y′(6, 0), and Z′(4, 2)

B.) X′(3, 0), Y′(0, 2), and Z′(2, 4)

C.) X′(4, 3), Y′(2, 0), and Z′(4, 2)

D.) X′(8, 3), Y′(6, 0), and Z′(4, 2)

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

can you put the picture up?

step-by-step explanation:

sure i'm up for it

step-by-step explanation: