Which statements are true about y Less-than-or-equal-to 8 and its graph? Check all that apply.
y = 0 is part of the solution set.
y = 8 is part of the solution set.
y = 10 is part of the solution set.
There is an open circle on the graph at 8.
There is a closed circle on the graph at 8.
The arrow on the graph points left.
The arrow on the graph points right.

When the inequality sign is </> (less than/greater than), the dot is an open circle.

When the inequality sign is ≤/≥ (less than or equal to/greater than or equal to), the dot is a closed circle.

y = number that is a solution/makes the inequality true

y ≤ 8      (y is any number less than or equal to 8)

#1:    y = 0 is part of the solution set.

Yes because if you substitute/plug in 0 into "y" in the inequality, since y = 0:

0 ≤ 8         0 is less than 8.

#2:     y = 8 is part of the solution set.

Yes because if you plug it into the inequality:

8 ≤ 8       8 is equal to 8

#3:     y = 10 is part of the solution set.

No because if you plug it into the inequality:

10 ≤ 8         10 is not less than or equal to 8

#4:     There is an open circle on the graph at 8.

No because the inequality sign is ≤, so there should be a closed circle on 8.

#5:      There is a closed circle on the graph at 8.

Yes because the inequality sign is ≤

#6:    The arrow on the graph points left.

Yes because if the arrow is pointing left then the numbers are decreasing, and y is any number less than or equal to 8.

#7:     The arrow on the graph points right.

No because if the arrow is point right then the numbers are increasing, but y is not a number greater than 8.

Your answer is the 1st, 2nd, 5th, and 6th option

you can not drow on this

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt