Log19–3x = log19(x + 5)

x = -5/4  if  this is log base 19,  or x = - 4.75 if these are common logs.

Step-by-step explanation:

log19–3x = log19(x + 5)

is the logarithm with base 19 ?

you could remove the log operation..

-3x =  (x + 5)

if it was the case that the logarithm was of base 19.

then

solve for x:

-4x = 5

x = -5/4

or if it was the case that this is a Common Logarithm then:

log  (19- 3x)  = log (19*(x + 5) )

19 - 3x = 19*(x + 5)

19 -3x = 19x + 95

-76 = 16x

x = -4.75

the answer is su.k.my? ? co.kc