"Ryanair charges a mean base fare of $59. In addition, the airline charges for checking in at the airport, carry-on baggage, checked baggage, and inflight food/beverage. These additional charges average $39 per passenger. Suppose a random sample of 60 passengers is taken to determine the total cost of their flight on Ryanair. The population standard deviation of total flight cost is known to be $25."

a. What is the probability the sample mean will be within $10 of the population mean cost per flight?
b. What is the probability the sample mean will be within $5 of the population mean cost per flight?
c. What is the probability the sample mean will exceed $100?

a) P=0.998

b) P=0.879

c) P=0.268

Step-by-step explanation:

The mean charges per passenger are:

The standard deviation is known to be σ=$25.

If the sample size is 60, we have to calculate:

a) the probability the sample mean will be within $10 of the population mean cost per flight.

This can be calculated from the z-value for a margin or error of 10 from the mean:

b) the probability the sample mean will be within $5 of the population mean cost per flight.

This can be calculated from the z-value for a margin or error of 5 from the mean:

c) the probability the sample mean will exceed $100

Again we will calculate the z-score for X=100.

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.