What is the height of a triangle whose base is 8.6 centimeters and whose area is 79.12 square centimeters? round to the nearest tenth

height = 18.4 cm

Step-by-step explanation:

A = (1/2)*b*h

A = 79.12 sq. cm = (1/2)* 8.6  *  h

A = 79.12 sq. cm = 4.3  *  h

h = 79.12 / 4.3  =  18.4 cm

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

step-by-step explanation:

where is the questions