A math club has 60 members. The number of girls is 6 less than 2 times the number of boys. How many members are boys? How many are girls?

22 boys, 38 girls

Step-by-step explanation:

First you create 2 equations x+y=60 and 2x=y+6 where x is the boys and y is the girls.

For 2x= y+6 , subtract 6 to both sides and you get y=2x-6.

Plug that into the first equation and you get 2x-6+x=60.  

Then, simplify and you get 3x - 6 = 60.

Add 6 from both sides and you get 3x = 66.

Divide by 3 and get x = 22.

Thats the number of boys in the math club.

To find the number of girls, just do 60-22 which is equal to 38.

There are 22 boys and 38 girls

Step-by-step explanation:

By reading this problem you can look for key words that will help you create equations, (this question is a systems of equations problem). Knowing that the math club has 60 members, the number of boys + girls = 60, also known as b + g = 60. Next, it says "the number of girls is 6 less than 2 times the number of boys" which can be translated to g = 2b - 6. Knowing that b + g = 60, subtract b and get g=60-b. Now you can replace g with 60-b in the equation g = 2b - 6, which now looks like this: 60-b = 2b - 6. Everything is in terms of b now so you can solve for the number of boys now! Add b to both sides and also add 6 to both sides. This gives 3b = 66 and by dividing both sides by 3, you get b=22. Now you know there is 22 boys and that there are 60 total people, so using the equation b + g = 60, 22+g=60, where you can subtract 22 from both sides to get g=38. This finally means there are 22 boys and 38 girls. Hope this helps! :)

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