On a coordinate plane, a line goes through (negative 2, negative 4) and (2, 2). A point is at (negative 3, 1).
What is the equation, in point-slope form, of the line that is parallel to the given line and passes through the point (−3, 1)?

y – 1=Negative three-halves(x + 3)
y – 1=Negative two-thirds(x + 3)
y – 1= Two-thirds(x + 3)
y – 1= Three-halves(x + 3)

y – 1= Three-halves(x + 3)

Step-by-step explanation:

line goes through  (-2, -4) and (2, 2)

goes through (-3, 1)

slope =  (-4 - 2) / (-2 -2)  = -6/-4 = 3/2

1 =  (3/2)*-3 + b

1 = -9/2 + b

b = 1 + 9/2 = 11/2 = 5.5

y = (3/2)*x + 11/2

(y - 1) = (3/2)(x + 3)

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )

other answer is correct. i had used the radius of the radius somehow. a website: