Solve the triangle. a = 12, b = 21, c = 94°

Hey mate!
You stuck?

C = 24.2, A = 28.7 degrees, B = 57.3 degrees.

Using the cosine law, c^2 = a^2 + b^2 - 2*a*b*cos(C), gives us

c^2 = 12^2 + 21^2 - 2*12*21*cos(94) = 620.157 ⇒  c = 24.9.

Next, using the sine law, sin(A) / a = sin(C) / c ⇒

sin(A) / 12 = sin(94) / 24.9 > A = arcsin(12*sin(94)/24.9) = 28.7 degrees.

Finally, B = 180 - A - C = 180 - 28.7 - 94 = 57.3 degrees. 

Hope this helps!

A=28.73091289
B=57.26908710
C=94
a=12
b=21
c=24.90295690

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