Find the radius of Circle O if DE = 12 inches and DE bisects OF.

Step-by-step explanation:

Given that,

DE bisects OF, then OB is equal to BF,

So, OB is ½r

Also, DB is equal to BE, so BE = DB = 6 in

So, applying Pythagoras theorem to triangle OBE

OB² + BE² = OE²

(½r)² + 6² = r²

¼r² + 36 = r²

Multiply through by 4

r² + 144 = 4r²

144 = 4r² - r²

144 = 3r²

r² = 144 / 3

r² = 48

r = √48

r = √16×3

r = 4√3 inches

r = 6.93 inches.

So, the radius of the circle is 4√3 inches

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

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about 0.75 hours

step-by-step explanation: