Does someone understand this ?

1. Line XY

2. Line XZ

3. (opposite angle): IU

(adjacent angle): IH

Question 1:

For the first problem, you are finding the opposite side to ∠YZX, by knowing that Z is the center of this angle, it is rather simple to solve.

Just draw your line through the middle of the angle through the triangle until you hit the side on the other side.

When doing this on question 1, you would pass between the angles of ∠X and ∠Y, therefore you are passing through line XY.

Question 2:

For the next problem, we need the adjacent angle to ∠YZX, in other words the one other line which is not the opposite angle.

By doing that we can rule it down to lines XZ and YZ, but it cannot be angle YZ because that is the hypotenuse of the triangle (the longest side) and cannot ever be the opposite or adjacent lines.

So, your answer for question 2 would be line XZ.

Question 3:

For the last problem, we need to find both the opposite and adjacent sides of the triangle according to angle ∠IHU.

So, firstly, do that finger through the center of the angle trick for the opposite angle and you would get line IU.

Then for the adjacent angle, find the hypotenuse and choose the one other angle that you haven't chosen as your opposite angle.

By doing that, you would get line IH.

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)