A baseball stadium holds 15,002 seats. The lower level has 50 fewer than three times as many seats as the upper

level. The middle level has 40 more than twice as many seats as the upper level.

x+ (2x + 40) + (3x - 50) = 15,002

Upper level = 2502 seats

Middle level = 5044 seats

Lower level = 7456 seats

Step-by-step explanation: given that

A baseball stadium holds 15,002 seats.

Let the Upper, middle and lower levels be represented as U, M and L respectively. And x = number of seat at the upper level

The lower level has 50 fewer than three times as many seats as the upper. That is

L = 3x - 50 (1)

The middle level has 40 more than twice as many seats as the upper level. That is

M = 2x + 40

Where L = x

x+ (2x + 40) + (3x - 50) = 15,002

You solved for x and found out the upper level has 2,502 seats . How many seats are in the lower level and how many seats are in the middle ?

That is x = 2502

Substitute x into equation 1

L = 3(2502) - 50

L = 7456 seats

Substitutes x into equation 2

M = 2(2502) + 40

M = 5044 seats