A charge q1 = 5 μC, is at the origin. A second charge q2 = -3 μC is on the x-axis 0.8 m from the origin. The electric field at a point on the y-axis 0.5 m from the origin is:

Step-by-step explanation:

The electric field is given by:

k: Coulomb's constant = 8.98*10^9 Nm^2/C^2

at the point P(0,0.5m) you have both x ad y component of the electric field. For the particle q1 you have:

for the particle q2, it is necessary to compute the angle between the E vector and the axis, by using the distance y and x. Furthermore it is necessary to know the distance from q2 to the point P.

Finally, by adding E1 and E2 you obtain:

the answer to this question is 3/19

step-by-step explanation:

30

step-by-step explanation:

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