When determining which x-values would make an expression undefined, you do not need to include the factors you canceled out.

True or false?

I think it’s false, but I’m not confident in my answer

This is truly false.

When determining which x-values would make an expression undefined, you do need to include the factors you canceled out.

Step-by-step explanation:

When working with functions, it is said to be undefined when the value of the function doesn't take on a value, and this occurs when the denominator is equal to 0.

Take for example

(x-2)/(x-2)

This simple function can be simplifted further by cancelling out the factors to get 1, but that doesn't change the fact that, at x=1, this function becomes undefined.

Because, the values of x can vary and can take on values that can make the denominator to be 0, factors that are cancelled need to be included in checking for where a function is undefined.

Hope this Helps

use google you idiot omg you're so annoying

step-by-step explanation:

207/8 is the right