Solve each equation for 0° < x < 360°.
cos(x+45°) + cos(x - 45°) = square root of...
Mathematics, 05.05.2020 17:33 tqjb2007
Solve each equation for 0° < x < 360°.
cos(x+45°) + cos(x - 45°) = square root of 2
a. 45
b. 10
c.0
d.90
Answers: 2
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