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Mathematics, 05.05.2020 17:33 tqjb2007

Solve each equation for 0° < x < 360°.

cos(x+45°) + cos(x - 45°) = square root of 2

a. 45

b. 10

c.0

d.90

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Answers: 2

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Solve each equation for 0° < x < 360°.

cos(x+45°) + cos(x - 45°) = square root of...
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