Se lanza un objeto desde una plataforma.
Su altura (en metros), xxx segundos después del lanzamiento, está modelada por:
h(x)=-5x^2+20x+60h(x)=−5x
2
+20x+60h, left parenthesis, x, right parenthesis, equals, minus, 5, x, squared, plus, 20, x, plus, 60
¿Cuál es la altura del objeto en el momento del lanzamiento?

The height of the object at launch is 60 meters.

Step-by-step explanation:

The question is:

An object is thrown from a platform.  Its height (in meters), x seconds after launch, is modeled by h (x) = - 5x^2 + 20x + 60. What is the height of the object at launch?

Solution:

The equation representing the height of the object x seconds after launch from the platform is:

In this case we need to compute the height of the object at launch, i.e. the height of the object at x = 0 seconds.

Compute the height of the object at x = 0 seconds as follows:

Thus, the height of the object at launch is 60 meters.

{3 + i, 3 - i, 3, -1}

step-by-step explanation:

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation: