A rectangular package sent by a postal service can have a maximum combined length and girth (perimeter of a cross sectio) of 108 inches. Find the dimensions of the package of maximum volume that can be sent, if the cross sectional region must be square.

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

Step-by-step explanation:

This is a optimization with restrictions problem.

The restriction is that the perimeter of the square cross section plus the length is equal to 108 inches (as we will maximize the volume, we wil use the maximum of length and cross section perimeter).

This restriction can be expressed as:

being x: the side of the square of the cross section and L: length of the package.

The volume, that we want to maximize, is:

If we express L in function of x using the restriction equation, we get:

We replace L in the volume formula and we get

To maximize the volume we derive and equal to 0

We can replace x to calculate L:

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

54 km / hours

step-by-step explanation:

we need to convert seconds to hours

60 seconds = 1 minutes

60 minutes = 1hour

15 m         60 second   60 minutes

  * *         = 54000 meters/ hour

second     1 minute             1 hour

now we need to convert meters to km

1000 m = 1 km

54000 m       1 km

*   = 54 km / hours

hour               1000m

answer: (1,3) (3,-1) (5,-5) ?

step-by-step explanation: