A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second.

EQUATION:

y=-16x^2+281x+137

It will take 18.04s for the rocket to hit the ground.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

In this problem:

Height given by the following equation:

It hits the ground when y = 0. So

Multiplying by -1

So

Then

It cannot take negative time, so we discard

It will take 18.04s for the rocket to hit the ground.

step-by-step explanation:

subtract 7, so the answer is x < = 3, or c.

hello i am doing good for you that it's summer in your country or state ; )

btw in my country we just have sun and rain as (because i live in the caribbean lol)

also, thx a lot for the points : )