The height of a triangle is 2 less than 5 times its base. If the base of the triangle is xfeet, and the area is 12 square feet, which equation mofles this situation

  Base of triangle = 2.4 Feet and Height of triangle = 10 feet.

Step-by-step explanation:

This problem can be solved by using formula to calculate area of triangle.

Area of triangle = 1/2*(base*height)

given

Let base of triangle B

height if triangle H

according to problem

The height of a triangle is 2 less than 5 times its base

mathematically it can be expressed as

H = 5*B - 2

Given area of triangle= 12 sq feet

Area of triangle = 1/2*(base*height)

=> 12 = 1/2* {B*(5*B-2)}

=> 24 = 5B^2 - 2B

  which is a  quadratic equation

It can be solved as given below

Since for side of triangle B cannot be negative number hence B= 12/5 = 2.4

Therefore height of triangle = 5*B - 2 = 5*2.4 - 2 = 12 - 2 = 10

Base of triangle = 2.4 Feet and Height of triangle = 10 feet.

Equation which models this situation is

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.