Since january 1, 1960, the population of slim chance has been described by the formula p=33000(0.98)^t where p is the population of the city t years after the start of 1960. at what rate was the population changing on january 1, 1978?

If  January 1, 1960, the population of Slim Chance has been described by the formula P=33000(0.98)^t where P is the population of the city t years after the start of 1960. The rate that the population change on January 1, 1978 is : 22,940

Let P=33000(0.98)^t

Let t = 18 (1978-1960)

Now let determine at what rate was the population changing on January 1, 1978

Change in population = 33000(0.98)^18

Change in population= 22,939.47

Change in population=22,940 (Approximately)

Inconclusion if  January 1, 1960, the population of Slim Chance has been described by the formula P=33000(0.98)^t where P is the population of the city t years after the start of 1960. The rate that the population change on January 1, 1978 is : 22,940

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Let

P-------> the population of Slim Chance (Since January 1, 1960)

t--------> the number of years (after the start of 1960)

we know that

Step 1

Take the derivative of P with respect to t

Step 2

Evaluate the derivative of P with respect to t for

substitute

therefore

the answer is

The rate of change is

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7 hours, 0 minutes, 0 seconds

or:  

0.04

total weeks

or:  

0.29

total days

or:  

7.00

total hours

or:  

420.00

total minutes

or:  

25,200.00

total seconds

step-by-step explanation: