Ann increased the quantities of all the ingredients in a recipe by 60%, percent. She used 80 grams (\text{g})(g)left parenthesis, start text, g, end text, right parenthesis of cheese. How much cheese did the recipe require?

The recipe required 50 grams of cheese

Step-by-step explanation:

Here in the question, we are made to know that she increased all ingredients by 60%.

Now we want to know the original mass of the cheese if she used 80grams after the 60% increment.

Mathematically, the formula for percentage increase is;

% increase = increment/old value * 100%

Where increment is new value - old value

since we do not know the old value, we can say that it is x. This means that the increment is 80-x

Hence;

60= (80-x)/x * 100

60x = 100(80-x)

60x = 8000-100x

100x + 60x = 8000

160x = 8000

x = 8000/160

x = 50g

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

answer is because 4×10=40

and 98×4= is 392

40,392