How do you solve this equation 3 1/2 + 2/3

Hi Selena

3 1/2 + 2/3

Multiply 2 by 3 and add it by 1 (for the first fraction)

6+1 / 2 + 2/3

7/2 + 2/3

Now we have different denominator, so we need to multiply the denominator together. 2* 3 = 6

Now we have 6. You need to divide 6 by 2 and add it by the numerator. do that for the second fraction

21/6 + 4/6

Same denominator just add the numerator

21+4/6

25/6

That's the answer.

I hope that's help:)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: