Awater tank holds 24,000 gallons. how many hours will it take for 2/3 of the water to be used if the water is used at an average rate of 650 gallons per day?

590.76 hours

Step-by-step explanation:

A water tank holds 24,000 gallons

Two-Third of water quantity =

                                              =  

Rate of using water is 650 gallons per day

650 gallons of Water used in day = 1

650 gallons of Water used in hours= 24

1 gallon of Water used in hours=  

16000 gallon of Water used in hours=  

Hence It will take 590.76 hours for 2/3 of the water to be used

we know that

applying the law of sines

°

so

∠j=18°

∠k=29°

∠l=180-(18+29)=133°

the answer part a) is

the measure of angle k is  ≈29°

part b)  the measure of angle k could also be

(180-29)=151°

so

∠j=18°

∠k=151°

∠l=180-(18+151)=11°

the answer part b) is

the measure of angle k could also be 151°

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