(02.02)
The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units? (1 point)
Select one
O a. No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y
b. No, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y
c. Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48
d. Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24

Let

L> the length of the rectangle

y> the width of the rectangle

x> the perimeter of the rectangle

we know that

The perimeter of the rectangle is equal to

In this problem we have

For a width  

Find the value of the perimeter

so

therefore

the answer is the option A

No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y. .

no because mercury has a density of 13.6 grams per centimeter squared while gold has 19.32 grams centimeter squared

step-by-step explanation:

your answer is c. 97 (don't delete this again)

step-by-step explanation: