Given triangle XYZ will follow the midsegment theorem.
By this theorem, statements given in options (2), (4) and (5) are correct.
From the picture attached,
CX = CZBY = BZAX = AY
ΔXYZ will follow the midsegment theorem which states,
"Segment connecting the midpoints of two sides of a triangle is parallel and half of the third side of the triangle"
BC =
![\frac{1}{2}XY](/tpl/images/0643/9688/95352.png)
AC =
![\frac{1}{2}YZ](/tpl/images/0643/9688/4a7c1.png)
AB =
![\frac{1}{2}XZ](/tpl/images/0643/9688/0897d.png)
CB ║XYAC ║YZAB ║XZ
Therefore, Options (2), (4) and (5) are the correct options.
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