A ball is launched from 8 off the ground at an initial vertical speed of 64 feet per second. It is aimed across at the field at a target also 8' off the ground. The heights of the ball at the time, t, in seconds is given by the function, h=-16t^2+64t+8. it will take the ball seconds to hit its target.

Step-by-step explanation:

8

step-by-step explanation:

this is a subtraction problem.

10 - 2 = 8

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine