Trish is solving for the zeros of the quadratic function f(x) = 2x2 – 3x + 3. x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction x = StartFraction negative (negative 3) plus or minus StartRoot (negative 3) squared minus 4 (2)(3) EndRoot Over 2 (2) EndFraction x = StartFraction 3 plus or minus StartRoot b 9 + 32 EndRoot Over 4 EndFraction x = StartFraction 3 plus or minus StartRoot 41 EndRoot Over 4 EndFraction Did Trish find the correct zeros of this function? Explain. Yes, those are the two real number zeros. No, the two real number zeros are StartFraction negative 3 plus or minus StartRoot 41 EndRoot Over 4 EndFraction. No, the two real number zeros are StartFraction 3 plus or minus StartRoot 41 EndRoot Over negative 4 EndFraction. No, the function has no real number zeros

Given: ad¯¯¯¯¯ is an altitude. prove: ab2+ac2=cb2 right triangle a b c with right angle a. point d lies on side b c and segment a d is drawn. angle a d c is a right angle. drag and drop a reason into each box to correctly complete the two-column proof. statement reason ad¯¯¯¯¯ is an altitude, and ∠bac is a right angle. given ∠adb and ∠adc are right angles. definition of altitude ∠bac≅∠bda ? ∠bac≅∠adc ? ∠b≅∠b ? ∠c≅∠c reflexive property of congruence △abc∼△dba ? △abc∼△dac aa similarity postulate abbd=cbab ? ab2=(cb)(bd) cross multiply and simplify. acdc=cbac polygon similarity postulate ac2=(cb)(dc) cross multiply and simplify. ab2+ac2=ab2+(cb)(dc) addition property of equality ab2+ac2=(cb)(bd)+(cb)(dc) substitution property of equality ab2+ac2=(cb)(bd+dc) ? bd+dc=cb segment addition postulate ab2+ac2=cb2 substitution property of equality