89 heads and 139 tails, what is the relative frequency for the event "heads"? Use pencil and paper.
Suppose each friend flips a coin 760 times. Is there a value you would expect the relative frequency
for the event "heads" to be close to?
IS
Friend 1
Friend 2
Friend 3
Frequency
Frequency
Frequency
Outcome
Outcome
Outcome
Heads
| Heads
Heads 21
Tails 51
Tails
Tails
55
The relative frequency for the event "heads" for Friend 1 is .
25

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

answer: b

step-by-step explanation: