Solutions to the differential equation dy/dx = xy^3 also satisfy d^2y/dx^2 = y^3 (1 + 3x^2 y^2). Let y = f(x) be a particular solution to this differential equation with f(1) = 2 write an equation for the line tangent to the graph of y = f(x) at x = 1. Use the tangent line equation from part (a) to approximate f (1.1). Find the particular solution to this differential equation with initial condition f(1) = 2.

it would be:

c.parallelogram.

answer: the distance

step-by-step explanation:

to calculate the distance d of a line segment with endpoints (x1, y1) and (x2, y2) use the formula d (x2 x1)2 (y2 y1)2. to calculate the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) use the formula

the domain of a function is the set of input values, x , for which a function is defined. the domain is shown in the left oval in the picture below. the function provides an output value, f(x) , for each member of the domain.

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx