The San Francisco football team plays better in fair weather. They have a 70% chance of winning in good weather but only a 20% chance of winning in bad weather. (a) If they play in the Super Bowl in Wisconsin and the weatherman predicts a 60% chance of snow that day, what is the probability that San Francisco will win. (b) Given that San Francisco lost, what is the probability that the weather was bad

a) 40% probability that San Francisco will win.

b) 80% probability that the weather was bad

Step-by-step explanation:

In this problem, there are these following probabilities:

60% probability of bad weather.

If there is bad weather, 20% probability of SF winning.

100-60 = 40% chance of good weather.

If there is good weather, 70% probability of SF winning.

(a) If they play in the Super Bowl in Wisconsin and the weatherman predicts a 60% chance of snow that day, what is the probability that San Francisco will win.

If it snows, 20% probability of winning. If it does not snow, 70% probability of winning.

0.2*0.6 + 0.7*0.4 = 0.4

40% probability that San Francisco will win.

b) Given that San Francisco lost, what is the probability that the weather was bad:

Conditional probability:

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: SF losing

Event B: Bad weather

P(A):

Probability of SF losing, which from a), is 0.6 = 60%.

P(A and B)

60% chance of snow. If it snows, 80% probability of SF losing. So

Then

80% probability that the weather was bad

144.50

step-by-step explanation:

21.5 x 13.4=288.10 divide by 2

sure i'm up for it

step-by-step explanation: