For this quadratic equation, what is the value of *
2x² + 3x – 6
b2 - 4ac;
O 51
O 64
O 57
O-39

b² - 4ac = 57

Step-by-step explanation:

To find the value of b² - 4ac

we first need to know the values of a b and c

comparing the quadratic equation given 2x² + 3x – 6   and the standard quadratic equation   ax² + bx + c

we will see that

a = 2      b =  3  and c = -6

b² - 4ac  = 3² -  4(2)(-6)

              =9 + 48

              =57

b² - 4ac = 57

look a the sides they are perpendicular

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.