A sample mean, sample size, and population standard deviation are provided below. Use the one-mean z-test to perform the required hypothesis test at the 10% significance level. x overbarequals18, nequals33, sigmaequals5, Upper H 0: mu equals 21, Upper H Subscript a: mu less than 21

We can see that so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly less than 21 at 10% of signficance.  

Step-by-step explanation:

Data given and notation  

represent the sample mean

represent the population standard deviation

sample size  

represent the value that we want to test  

represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is less than 21 or no, the system of hypothesis would be:  

Null hypothesis:  

Alternative hypothesis:  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

(1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

P-value  

Since is a left side test the p value would be:  

Conclusion  

We can see that so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly less than 21 at 10% of signficance.  

im not sure

step-by-step explanation:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.