Triangle ABC has a perimeter of 22cm I WILL MARK YOU AS BRAINLIEST
AB=8cm
BC=5cm
By calculation deduce whether triangle ABC is a right angles triangle
please help

Step-by-step explanation:

Number of vertices

3

Variable constraints

a>0 and b>0

Diagonal lengths

(data not available)

Height

b

Area

A = (a b)/2

Centroid

x^_ = (a/3, b/3)

Mechanical properties:

Area moment of inertia about the x-axis

J_x invisible comma x = (a b^3)/12

Area moment of inertia about the y-axis

J_y invisible comma y = (a^3 b)/12

Polar moment of inertia

J_zz = 1/12 a b (a^2 + b^2)

Product moment of inertia

J_x invisible comma y = -1/24 a^2 b^2

Radii of gyration about coordinate axes

r_x = b/sqrt(6)

r_y = a/sqrt(6)

Distance properties:

Side lengths

a | sqrt(a^2 + b^2) | b

Hypotenuse

sqrt(a^2 + b^2)

Perimeter

p = sqrt(a^2 + b^2) + a + b

Inradius

r = 1/2 (-sqrt(a^2 + b^2) + a + b)

Circumradius

R = 1/2 sqrt(a^2 + b^2)

Generalized diameter

sqrt(a^2 + b^2)

Convexity coefficient

χ = 1

Mean triangle area

A^_ = (a b)/24