A man who moves to a new city sees that there are two routes he could take to work. A neighbor who has lived there a long time he tells him Route A will average 5 minutes faster than Route B. The man decides to experiment. Each day he flips a coin to determine which way to go, driving each route 10 days. He finds that Route A takes an average of 49 minutes, with standard deviation 2 minutes, and Route B takes an average of 50 minutes, with standard deviation 4 minutes. Histograms of travel times for the routes are roughly symmetric and show no outliers. (alpha =0.05)
Find a 95% confidence interval for the difference between the Route B and Route A commuting times.

The 95% confidence interval for the difference between the Route B and Route A commuting times is -3.771808 to 1.771808

Step-by-step explanation:

Here we have the confidence interval is given by the following equation;

= 49 Minutes

σ₁ = 2 Minutes

= 50 Minutes

σ₂ = 4 Minutes

n₁ = n₂ = 10 days

α = 0.05

At 95%, from the z score table , z = 1.959964 ≈ ± 1.96

Plugging in the values Solving we get

Δμ Min = -3.771808 and Δμ Max = 1.771808.

is means division by fractions

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.