A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observation from sample 1 are Xi and the observations from sample 2 are Yi, and di, = Xi - Yi, then the null hypothesis is H0 : \mu d+= 0 and the alternative hypothesis is H1 : \mu d 0.A researcher wants to show the mean from population 1 is less than the mean from population 2 in matched-pairs data. If the observations from sample 1 are Xi and the observations from sample 2 are Yi, and di = Xi - Yi, then the null hypothesis is H0 : \mu d = 0 and the alternative hypothesis is H1 : \mu d (choose answer below) 0.a. \neqb. <
c. >d. \leqe. \geq

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12